IMPORTANT:
If you're trying to factor a quadratic in Algebra I:There are no two integers that can solve this problem!
Your quadratic is <em>prime</em>!
If you're trying to solve a quadratic (find x):The factoring approach will not work for the same reasons listed above.
Try using splitting the middle or the quadratic formula instead.
Here's how you would solve it from a more advanced approach.
If you don't know what this stuff is, just ignore it.
ab = -18, a + b = -9
Find a in terms of b.
a = -9-b
Substitute this for a in the first equation.
(-9-b)b = -18
-9b-b² = -18
Multiply everything by -1 to get rid of all these negative signs.
b² + 9b = 18
Bring over that 18.
b² + 9b - 18 = 0
Apply the quadratic formula.
(a = 1, b = 9, c = -18)

If you need to write two distinct numbers, just write out one with a + and one with a - in place of the plus-minus sign.
Bearing in mind that, there are
60 seconds in 1 minute,
60 minutes in 1 hr,
1000 meters in 1 km,
and 1.609 km in 1 mile
If we rewrite it as y=mx+d (which can be taken from here from subtracting ax and c from both sides, then dividing b, resulting in y=(-a/b)(x)-c/b. We can then substitute -a/b for m and -c/b for d), if d=0, then we have m as a constant and as we add a specific number to y (that number being m) every time the x value increases by 1, it therefore forms a straight line. If d is not 0, then we simply add d to every single number - this is still a straight line due to that we still add a specific number to y every time x increases by 1 every single time
<span>What will be the cost of the glass to cover the picture?
</span>
D.$21.78