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scoundrel [369]
3 years ago
6

Fireside Flowers has 75 daisies, 60 lilies, and 30 roses. What is the greatest common factor Fireside Flowers can use to divide

the flowers into equal groups?
Mathematics
1 answer:
Elza [17]3 years ago
4 0
The greatest common factor of 30, 60, and 75 is 15.
15 x 2 = 30
15 x 4 = 60
15 x 5 = 75
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Which of the following could be a function with zeros of —3 and 2? А f(x) = (x - 3)(x + 2) B f(x) = (x = 3)(x - 2) © f(x) = (x+3
Zinaida [17]

Answer:

C

Step-by-step explanation:

to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2

6 0
3 years ago
A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle
hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

5 0
3 years ago
Explain why it is correct to claim that A/B < B/A is true.
PolarNik [594]

Answer:

Think of it as a small number and a large number. If the large number is being divided by a small number, of course that would be larger than the small number being divided by the large number.

3 0
3 years ago
Please I need someone to help my assignment​
Nadusha1986 [10]
(x-4)² + (x-2)² = x²

(x² - 8x + 16 ) + (x² - 4x + 4) = x

2x² -12x + 20 = x

2x²-12x + 20 - x = 0

2x² - 13x + 20 = 0

(2x-5) (x-4) = 0

2x-5 = 0

2x = 5

x = ⁵/₂


x-4 = 0

x = 4



so x₁ = ⁵/₂ , and x₂ = 4
4 0
2 years ago
Question in picture please help!
EleoNora [17]

Answer:

part a is A and E

Step-by-step explanation:

I had token the test

3 0
2 years ago
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