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scoundrel [369]

3 years ago

6

Fireside Flowers has 75 daisies, 60 lilies, and 30 roses. What is the greatest common factor Fireside Flowers can use to divide

the flowers into equal groups?

1 answer:

Elza [17]3 years ago

4 0

The greatest common factor of 30, 60, and 75 is 15.
15 x 2 = 30
15 x 4 = 60
15 x 5 = 75

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Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,

Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
$I(g,1,8)=5$
$I(f,5,8)=4$
$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

for some constant scalars $k,\ell$ .

Also, if $a\ge b$ , then

$I(f,a,b)=-I(f,b,a)$

a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

4 0

3 years ago

HELP ME PLEASE THIS IS DUE TMR

sweet-ann [11.9K]

What exactly do you need help with?

8 0

3 years ago

Use the data to create a scatter plot.

soldier1979 [14.2K]

I'm not sure about the given data but I plotted the scatter plot based on what I understand on how the data should be presented.

Time (years)
3, 6, 9, 12, 15, 18, 21, 24

Number of participants(x1000)
22, 25, 28, 14, 17, 20,15, 9

Attached is the scatter plot created online.
x = time (years)
y = number of participants

6 0

3 years ago

Which group of ordered pairs are on the line given by the equation 5−2=6

Zolol [24]

Answer: (0,-3)

Explanation: use desmos.con it will help! :)

8 0

3 years ago

standard automobile license plates in a country display 3 numbers, followed by 2 letters, followed by 2 numbers. how many differ

RoseWind [281]

The system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

<h3>Define the term permutation?</h3>

The number of potential arrangements for a given set is assessed mathematical terms, but this procedure is referred to as permutation.
The arrangement's order is essential when using permutations.

For the stated data;

Standard car license plates in a nation typically have 3 digits, 2 letters, and 2 numbers.

There are total 9 digits (0 - 9).

There are total 26 letter (A - Z)

Repetitions of letters and numbers given allowed.

Thus, numbers and the letters ca be arranged as;

1st place = 9 ways.

2nd place = 9 ways.

3nd place = 9 ways.

4th place = 26 ways.

6th place = 26 ways.

7th place = 9 ways.

8th place = 9 ways.

Total ways = 9×9×9×26×26×9×9

Total ways = 39917124

Thus, the system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

To know more about the permutation, here

brainly.com/question/1216161

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5 0

1 year ago