Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

Answer 1

Equation of circle is:

$x^2+y^2-6x+4y - 12 = 0$

Further explanation:

We have to use the standard form of equation of a circle to find the equation of circle from given details

The general equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

Given

Centre = (h,k) = (3, -2)

Radius = r = 5

Putting the values in the general equation

$(x-3)^2+(y-(-2))^2 = (5)^2\\(x-3)^2+(y+2)^2 = 25\\(x^2-6x+9)+(y^2+4y+4) = 25\\x^2+y^2-6x+4y+9+4-25 = 0\\x^2+y^2-6x+4y - 12 = 0$

Keywords: Circles, Equation of circle

Learn more about circles at:

• brainly.com/question/13063819
• brainly.com/question/8618791

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