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sukhopar [10]
3 years ago
12

PLEASE HELP I WILL AWARD BRANLIEST - 4 kitchen assistants can prepare 10kg of vegetables in 45 minutes. How long would it take 1

5 assistants to prepare the same amount?

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:

12 minutes

Step-by-step explanation:

We need to find the total amount of work time to do the job

4 * 45 = 180 work minutes

We now get 15 assistants, so take the work time and divide by the assistants

180 / 15 =12

They will need 12 minutes

Sunny_sXe [5.5K]3 years ago
3 0

Answer:

hi your answer is in the image

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Viktor [21]

9514 1404 393

Answer:

  • A: j = 25 +55h
  • B: m = 50 +30h
  • 1 hour

Step-by-step explanation:

We're going to say Job A is the charge at Jim's shop. For h hours, that charge will be the sum of the parts cost and the hourly charge:

  j = 25 +55h

Job B is the charge at Myron's shop. Similarly, that charge is ...

  m = 50 +30h

__

The two charges are equal when ...

  j = m

  25 +55h = 50 +30h

  25h = 25 . . . . . . . . . . . subtract 25+30h from both sides of the equation

  h = 1 . . . . . . . . . . divide by 25

The charges are the same at the two shops for 1 hour worked.

_____

<em>Additional comment</em>

You may be expected to write your equations using y for the charge and x for the hours. I like to use variable names that remind me what they stand for.

__

In general, when you have rates that have different fixed fees and different per-quantity costs, the "break even" quantity is the ratio of the difference in fees to the difference in per-quantity costs. Here the parts (fees) differ by $25, and the per-hour cost differs by $25, so the number of hours is 25/25 = 1 to make the charges equal.

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masya89 [10]

Step-by-step explanation:

1100-825= Markup

Markup= 275

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