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beks73 [17]
3 years ago
5

The sum of the areas of two circles is 80 pi square meters find the length of the radius of a radius of each circle if one of th

em is twice the orher
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0
Let x=small circle
2x = bigger circle

πx^2 + π(2x)^2 = 80π
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 16
x = +/- 4
but we need the positive one because there's no negative measurement so
the answers are:
4m and 8m
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Estimate the perimeter and area of the figure to the nearest whole number. Please help!!
solniwko [45]

Answer:

29 ; 37

Step-by-step explanation:

The figure is composed by a square, a rectangle, and a right triangle

The perimeter of the square is 6 units

The perimeter of the rectangle is 10 units

The triangle is composed by a side of 6 units and a side of 5 units

The third side can be find with the Pythagorean theorem

\sqrt{6^2 + 5^2} = \sqrt{36 + 25} = \sqrt{61} = 7,81025

The total perimeter is

6 + 10 + 5 + 7,81025 = 28,81025 = 29

Area of the square = 2^2 = 4 square units

Area of the rectangle = 6 x 3 = 18 square units

Area of the triangle =  (5 x 6)/2 = 15 square units

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A regular dodecagon is a polygon with 12 equal sides.
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Length of the apothem = (9/2)/tan 15 = 9/2tan 15 = 16.79 cm

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Natasha_Volkova [10]

The equation of the asymptote is y=1

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The given equation is f(x)=3^{x-5}+1

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Therefore, we have,

k=1

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Therefore, the asymptote of the equation is y=1

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