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3 years ago

What is the intersection of the sets A = {2, 3, 5, 7, 11} and B = {5, 11, 13, 15, 17}?

Mathematics

2 answers:

EleoNora [17]3 years ago

8 0

Answer:

A ∩ B = {5, 11}

Step-by-step explanation:

Hello, the intersection of two sets A and B (A B), is the set that contains all elements of A that also belong to B , I mean , the common elements

Step 1

Let

A = {2, 3, 5, 7, 11}

B = {5, 11, 13, 15, 17}

you have to verify the common elements, first order the data from least to greatest to make it easier, here they are already sorted

A ∩ B = {5, 11}

Have a great day

AleksAgata [21]3 years ago

6 0

The intersection of sets is composed of the common elements.

The given sets have two common elements: 2 and 5.

{2;3;5;7}∩{2;5;11;13}={2;5}

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 a

Ugo [173]

The question is incomplete. I am writing the complete question below:

The prostate-specific antigen (PSA) test is a simple blood test to screen for prostate cancer. It has been used in men over 50 as a routine part of a physical exam, with levels above 4 ng/mL indicating possible prostate cancer. The test result is not always correct, sometimes indicating prostate cancer when it is not present and often missing prostate cancer that is present. Suppose that these are the approximate conditional probabilities of a positive (above 4 ng/ml) and negative test result given cancer is present or absent.

Positive Result Negative Result

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Cancer Absent 0.06 0.94

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What is the probability that the test is positive for a randomly chosen person from this population? (Enter your answer to five decimal places.)

P(Positive test) =

Answer:

P(Positive Result) = 0.0699

Step-by-step explanation:

We are given that 6.6% of the population has prostate cancer. So,

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We need to find the probability that the result is positive. It can be either that the result is positive and cancer is present or the result is positive and the cancer is absent. So,

P(Positive Result) = P(Positive Result∩Cancer Present) + P(Positive Result∩Cancer Absent)

= P(Positive Result | Cancer Present)*P(Cancer Present) + P(Positive Result | Cancer Absent)*P(Cancer Absent)

= (0.21)*(0.066) + (0.06)*(0.934)

= 0.01386 + 0.05604

P(Positive Result) = 0.0699

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