(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
Answer:
10/√2
To rationalize multiply the numerator and denominator by the surd in the denominator
10/√2×√2/√2
=10√2/2
Answer:
x = -6
Step-by-step explanation:
Here we have an equilateral triangle. All three sides have the same length, 2. Therefore, the interior angles are all equal to 60 degrees.
Therefore, 6 - 9x = 60, and -9x = 54. Dividing both sides by -9 results in
x = -54/9, or x = -6.
Y2-y1 over x2-x1 (slope intercept form)
