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svet-max [94.6K]
3 years ago
11

How do I solve and whats the answer?

Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer:

x = -6

Step-by-step explanation:

Here we have an equilateral triangle.  All three sides have the same length, 2.  Therefore, the interior angles are all equal to 60 degrees.

Therefore, 6 - 9x = 60, and -9x = 54.  Dividing both sides by -9 results in

x = -54/9, or x = -6.

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3,500,000,000

Step-by-step explanation:

the exponent symbolizes how many places the decimal moves. since its positive, it moves to the right. if it where a negative exponent then it would move to the left.

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Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter
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Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\

since s(t) is the arc length for r(t), which is define as

s(t)=\int\limits^t_0 {||r'(t)||} \, dt

if we substitute the value of r'(t) we arrive at

s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\

s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }

substituting the value of t in to the given vector equation we have

r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k

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Step-by-step explanation:

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Step-by-step explanation:

Range of the data set provides us with some basic information regarding spread of the data.

It is commonly used and quite easy to find.

First step is to arrange the values from the lowest to the highest.

It is already given arranged, so that will savd us some time.

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