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Mandarinka [93]
3 years ago
8

The ratio of the prices of Emma's phone to Sophie's phone is 7:8. If Sophie's phone costs $640, how much should the prices of th

eir phones decrease in order to have a ratio of 9:11 ?
Mathematics
1 answer:
alekssr [168]3 years ago
4 0

Let cost of Emma's phone = x

Given that cost of Sophie's phone = 640

Then ratio of their phones cost will be x:640 or x/640

Given that ratio of their phones cost is 7:8 or 7/8

So both ratios will be equal.

\frac{x}{640}=\frac{7}{8}

x=\frac{7}{8}*640

x=560


So the new ratio of the cost of their phones will be 560:640

Now we have to find about how much should the prices of their phones decrease in order to have a ratio of 9:11.

So let that decreased amount is k then we will get equation :

\frac{560-k}{640-k}=\frac{9}{11}

11(560-k)=9(640-k)

6160-11k=5760-9k

6160-5760=11k-9k

400=2k

200=k


Hence final answer is prices of their phones should decrease by 200 in order to have a ratio of 9:11.

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Prove that the relation R is reflexive

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