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Tom [10]
3 years ago
9

I need help with solving this quadratic equation by factoring. the problem I need help with is number 5.

Mathematics
1 answer:
otez555 [7]3 years ago
4 0
I think it is - - (4/3), 3/2
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Give the radius or diameter. find the the circumference and area of each circle to the nearest tenth. Use 3.14 for pi
Vesnalui [34]

Answer:

A=π×r×r

r=D/2=24/2=12ft

A=3.14×12×12=452.16ft2

C=2πr

C=2×3.14×12

C=75.36ft

6 0
3 years ago
Converse of Pythagorean theorem, Find the missing side length of each triangle round to the nearest 10th if necessary.
torisob [31]

The formula for the Pythagorean theorem is,

\text{Hypotenuse}^2=Opposite^2+Adjacent^2

8 0
11 months ago
HELP MATH QUESTION GEOMETRY
schepotkina [342]

Angle COD equals angle AJL

Angle DCO equals Angle LAJ

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3 years ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0
3 years ago
Find the mid point of PQ if P (0,0) and Q (5, 12)
Simora [160]
Using the midpoint formula we get:

(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
5 0
3 years ago
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