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mariarad [96]
3 years ago
9

The length of a rectangular sign is 4 times its width. If the sign’s perimeter is 20 inches, what is the sign’s area?

Mathematics
1 answer:
likoan [24]3 years ago
3 0

Answer:

1,600 cubic inches

Step-by-step explanation:

1. we know that one side is 20 and the other side is 20 x 4

2. 20 x 4 = 80

3. multiply both sides to find area so 80 x 20 = 1,600 cubic inches

I hope this answers your question!

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oshua tracks the points he scores in 10 basketball games. In two games Joshua scored 8 points each, in one game he scored 3 poin
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II. Round to the nearest hundred.
julia-pushkina [17]

Answer:

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8 0
2 years ago
A cube is built with inside dimensions of 10 inches. The material is 0.2 inches thick. Use a Taylor series approximation to find
larisa86 [58]

Answer:

V(x,y,z) ≈ 61.2 in

Step-by-step explanation:

for the function f

f(X)=x³

then the volume will be

V(x,y,z)= f(X+h) -  f(X) , where h= 0.2 (thickness)

doing a Taylor series approximation to f(x+h) from f(x)

f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!

that can be approximated through the first term and second

f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2

since x=L=10 in (cube)

f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)

then

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V(x,y,z) ≈   61.2 in

V real = (10.2 in)³-(10 in)³ = 61 in

8 0
3 years ago
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