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balandron [24]
3 years ago
11

. Given that 3 of the 64 possible codons are stop codons, what is the chance of having a stop codon at any given position, assum

ing that the sequence is random?
Biology
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

1 - (\frac{61}{64})^n

Explanation:

Given

There are three stop codon

TAA, TAG, TGA.

Out of 64 available codons, 3 are stop codon thus the remaining are non-stop codon.

So the probability of choosing a non stop codon is

\frac{61}{64}

Let us suppose the number of trials are "x" then the probability of choosing a non stop codon is  

(\frac{61}{64})^x\\

Probability of choosing a stop codon is equal to

1 - probability of choosing a non stop codon

1 - (\frac{61}{64})^n

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