Answer:
100
Step-by-step explanation:
it is a bit unclear to me, what that problem description means.
if I understand it correctly, than z is directly depending on x².
so, z = 16 for x = 2. x² = 4
I pondered a little bit, as there are several possibilities to connect 16 with 4 as a driving factor (e.g. 2⁴ = 16, 4×4 = 16, 12 + 4 = 16).
I decided to go with the simplest interpretation with the usual meaning of "varies" (multiplication) : 4×x²
that would mean
z = 4×x² = 4×5² = 4×25 = 100
A direct variation suggest that the value of x in the equation would greatly affect the value of y such that when x is increasing, y also increases and the other way around. The equation for a direct variation is that,
y = kx
Substituting the given values in the ordered pair,
5 = k(4) ; k = 5/4
We know, Circumference of a Circle = 2πr
C = 2 * 22/7 * 3.5
C = 2 * 22/2
C = 2 * 11
C= 22
In short, Your Answer would be 22 Feet
Hope this helps!
Addition and subtraction of an equilater of what?
<u>Solution-</u>
From the figure,
AE = 2.4
EB = 2.8
BC = 11.7
Area of rectangle 1 = 8.68 sq.in

(∵ sides of the rectangle 2)
Area of Triangle 1 = 6.48 sq.in


(∵ sides of the rectangle 1)


(∵ sides of the rectangle 2)



The area of Rectangle 2,

The area of Triangle 2,

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2
= 6.48+8.68+8.82+6.44=30.42 sq.in