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kolbaska11 [484]
3 years ago
9

Four consecutive integer numbers add to 2. What are the numbers?

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0

Four consecutive integer numbers add to 2. What are the numbers?

Let the smallest integer=x

The three consecutive integers will be x+1,x+2, x+3

Sum of four consecutive integers=2

So, x+x+1+x+2+x+3=2

Adding like terms, we get

4x+6=2

Subtract 6 from both sides

4x+6-6=2-6

4x+0=-4

4x=-4

To solve for x, let us divide by 4 on both sides

4/4x=-4/4

x=-1

So, the four consecutive integers are =x=-1

x+1=-1+1=0

x+2=-1+2=1

x+3=-1+3=2

So, the four consecutive integers are:= -1,0,1,2

il63 [147K]3 years ago
3 0
The numbers would be -1, 0, 1, 2.
Hope this helps
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Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.
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Answer:

Option (1)

Step-by-step explanation:

x               -2              -1                 0                    1                   2

y               10            2.5                0                  2.5                3.0

Ist difference,

d_1=y_2-y_1

    =2.5-10=-7.5

d_2=y_3-y_2

    =0-2.5

    = -2.5

d_3=y_4-y_3

    =2.5-0

    = 2.5

d_4=y_5-y_4

    =10.0-2.5

    = 7.5

2nd difference,

x_1=d_2-d_1

    =-2.5+7.5

    = 5

x_2=d_3-d_2

    =2.5+2.5

    = 5

x_3=d_4-d_3

    =7.5-2.5

    = 5

Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

2.5 = a(1)² + b(1)

a + b = 2.5 ------(2)

By adding equations (1) and (2),

2a = 5

a = 2.5

and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

8 0
3 years ago
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