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Sergeu [11.5K]
3 years ago
8

If Y is the midpoint of AB, find B given A(3,5) and Y(-2, 3).*

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer: (-7,1)

Step-by-step explanation:

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Answer:

D and E

Step-by-step explanation:

27 and 50 are greater than 20. The scale factor is more than 1, so the answer(s) have to be more than 1.

3 0
3 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

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8 is the correct answer 
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3 years ago
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See photo for solution and mark me as brainliest if you think i helped!

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