A car has a 16-gallon fuel tank. When driven on a highway, it has a gas mileage of 30 miles per gallon. The gas mileage (also ca
2 answers:
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Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
Answer:
Step-by-step explanation:
Picture 1
In right triangle ABC,
Side AB is the opposite side of angle C.
Picture 2
In triangle MKL,
tan(∠M) =
=
=
Option (1) is the answer.
Picture 3
In ΔXYZ,
sin(∠Z) =
=
For the length of XY we will apply Pythagoras theorem in ΔXYZ,
XZ² = XY² + YZ²
XY² = XZ² - YZ²
= (40)² - (32)²
XY = √576
= 24
sin(Z) =
sin(Z) =
Picture 4
In right triangle DEF,
Cos(D) =
=
=
=
Picture 5
In ΔABC,
tan(63°) =
tan(63°) =
AB =
AB =
AB = 4.0762 ≈ 4 m
Option (3) will be the answer.
There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
' in a right triangle, '
' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:
Now, we solve for x:
So, answer is 3.4
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
So, for this setup:
Now, we solve for x:
So, answer is 3.4