Question

What is the approximate value of log6 1944 if log6(9)is approximately 1.2263

Answer 1

$log_{6}(1944) = log_{6}(324 \times 6) \\ log_{6}(18 {}^{2} \times 6) = log_{6}((3 \times 6) {}^{2} \times 6) \\ log_{6}(3 {}^{2} \times 6 {}^{2} \times 6) \\ \\ log_{6}(9) + log_{6}(6 {}^{3} ) = 1.2263 + 3 \\ 4.2263$