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3 years ago

What is the approximate circumference of a semicircle with a radius of 35 inches?

2 answers:

6 0

I think: C. 109.9 inches;
Considering that the entire circumference is $2 \pi r$ a semicircle should be only: $\pi r=3.14*35=109.9 in$

kakasveta [241]3 years ago

3 0

If it were a complete circle, its circumference would be

(π) x (diameter) = (π) x (2R) = 70 π inches .

Since it's only half of the circle, the length of the curved part is

70 π / 2 = 35 π = 109.9 inches .

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Answer:

288

Step-by-step explanation:

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3 years ago

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Find the area of the region between two concentric circular paths. If the radii of the circular paths are 210 m. and 490 m. resp

taurus [48]

Given :

The radii of the circular paths are 210 m. and 490 m.

To Find :

The area of the region between two concentric circular paths.

Solution :

Area of the outer circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}}$

⠀

Area of the inner circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}}$

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Therefore,

Area of the region inside the circular paths :

$\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}$

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6 0

2 years ago

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Answer:

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Step-by-step explanation:

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when x = 4

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2 years ago

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Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the

Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

Solution:

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

$\text{Distance}=\text{Speed}\times\text{Time}$

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

$\Rightarrow6x+18+6x = 162$

$\Rightarrow12x=162-18$

$\Rightarrow x=\frac{144}{12}\rightarrow x=12$

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be $x+3=12+3=15 \text{ mph}$

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3 years ago

3/2000 as a decimal

Anarel [89]

Decimal

3/2000 = 0.0015

4 0

4 years ago