I believe the answer is: -190.98
Answer:
B. 4 imaginary; 1 real
Step-by-step explanation:
Given the polynomial:
x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7
it can be reordered as follows
(x^5 + 2*x^3 + x ) + (7*x^4 + 14*x^2 + 7)
Taking greatest common factor at each parenthesis
x*(x^4 + 2*x^2 + 1) + 7*(x^4 + 2*x^2 + 1)
Taking again the greatest common factor
(x + 7)*(x^4 + 2*x^2 + 1)
Replacing x^2 = y in the second parenthesis
(x + 7)*(y^2 + 2*y + 1)
(x + 7)*(y + 1)^2
Coming back to x variable
(x + 7)*(x^2 + 1)^2
There are two options to find the roots
(x + 7) = 0
or
(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0
In the former case, x = -7 is the real root. In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.
Answer:
-625
Step-by-step explanation:
Here we are basically multiplying each term by -5. So if you want two more terms, you would go like this...
5 × -5 = -25
-25 × -5 = 125
125 × -5 = -625
-625 × -5 = 3125
and so on!!!
Hope it helps and mark it as Brainliest if possible!!! Good Luck!!!
Answer:
y-13=-7/2(x+4)
Step-by-step explanation:
y-y1=m(x-x1)
where m=slope and (x1, y1) is a point on the line
m=(y2-y1)/(x2-x1)
m=(6-13)/(-2-(-4))
m=-7/(-2+4)
m=-7/2
y-13=-7/2(x-(-4))
y-13=-7/2(x+4)
Answer:
x=4
Step-by-step explanation:
