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3 years ago

Please help asap?......

Mathematics

1 answer:

andriy [413]3 years ago

6 0

Answer:

Step-by-step explanation:

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After proving ADB is congruent to CDB, how can you prove that < ADB is congruent to < CDB ?

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Answer:

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3 years ago

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VLD [36.1K]

Answer: ECB and ABC

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2 years ago

Complete the square for 5x^2+10x-16. first one to answer gets brainiest

ella [17]

Answer: x= -1 + √(21/5)

Step-by-step explanation:

The given equation can be written as 5x^2+10x-16=0

keep the x terms on one side and constant on another side

5x^2+ 10x = 16.

Now, to make a complete square like (x+a)^2 = x^2+2xa+a^2.

Divide the given equation by 5 on both sides,

The equation now becomes x^2+2x = 16/5.

The middle term is 2xa=2x

By solving for term "a" in above equation, a= 1

The entire equation of complete square should be x^2+2x+1, which is equal to (x+1)^2

Here, in the equation given in question, +1 is missing to make a complete square.

In order to add 1 we have to simultaneously minus 1 to keep the values in the equation unchanged.

Thus, x^2+2x+1-1 =16/5.

Again moving the constant -1 to other side, we have

x^2+2x+1 =16/5+1

After simplification,

(x+1)^2= 21/5

Taking square root on both sides,

(x+1)= + √(21/5)

The answer is x= -1 + √(21/5)

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3 years ago

Y=Cosx.arcsinx What is the solution

Alinara [238K]

Step-by-step explanation:

Given: $y = cos(sin^{-1}x))$

As the domain for the inverse sine function is 1 ≤ x ≤ 1 as this is the range for the sine function.

The range for the function is the same as the range for the cosine function, 1 ≤ y ≤ 1

$sin^{2}x +cos^{2}x = 1$

So, using the identity $cos(x) = \pm \sqrt{1-sin^{2}(x) }$

$y = \pm \sqrt{1-sin^{2}(sin^{-1}(x)) }$

As the sin and inverse sin function do cancel each other, so only x² is left.

Hence,

$y = \pm \sqrt{1-x^{2}$ ; $-1\leq x\leq 1$

Keywords: trigonometric function

Learn more trigonometric function from brainly.com/question/12551115

#learnwithBrainly

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4 years ago

How do I find the slope of the line containing the two points (9,0) and (-5,6)

deff fn [24]

Slope Formula: $\frac{y_2-y_1}{x_2-x_1}$

So using the slope formula, plug in the two points and solve for it as such:

$\frac{0-6}{9-(-5)}=-\frac{6}{14}\div \frac{2}{2}=-\frac{3}{7}$

The slope is -3/7.

7 0

4 years ago