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Sophie [7]
3 years ago
6

What is the approximate circumference of a circle with a diameter of 9? Round answer to nearest tenth.​

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer:

113.1

Step-by-step explanation:

Write down the equations on the top of your paper; it could help you throughout your homework.

The equation for circumference is 2 times pi, times the radius.

The Radius is the diameter times two.

2 times 9=18, so therefore the radius is 18.

Once you have that done, just put in your calculator 2 times pi times 18.

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PLS HURRY! WILL MARK BRAINLIEST
defon

Answer:

 A=941.33 square inches.

Step-by-step explanation:

The total area of the banner is the sum of the areas of the square and the semicircle (half cricle) The side length of the square is 26 inches and the radius of the semicircle is 13 inches (half of the dimeter) so: A=Asquare+Asemicircle A=(s2)+(12)πr2 A=262+12(3.14)(13)2 A=676+265.33

5 0
2 years ago
I need help. I'm stuck on this one
inna [77]
Add 5/9 to both sides. common denominator would be 72 so you would multiply the top and bottom of 3/8 by 9 (bc 9x8 is 72) to get 27/72. you would multiply top and bottom of 5/9 by 8 to get 40/72 and you would add 40+27 which equals 67 so x=67/72 i believe
4 0
3 years ago
Read 2 more answers
Choose the best answer:
Oksi-84 [34.3K]

Answer:

The length of the hypotenuse is 2 square root of 13 ⇒ c

Step-by-step explanation:

The rule of the area of the right triangle is A = \frac{1}{2} × leg1 × leg2, where

leg1 and leg2 are the sides of the right angle

∵ The area of a right triangle is 12 in²

∵ The ratio of the length of its legs is 2: 3

→ Let leg1 = 2x and leg2 = 3x

∵ leg1 = 2x and leg2 = 3x

→ Substitute them in the rule of the area above

∴ 12 = \frac{1}{2} × 2x × 3x

∵ 2x × 3x = 6x²

∴ 12 =  \frac{1}{2} × 6x²

∴ 12 = 3x²

→ Divide both sides by 3 to find x²

∴ 4 = x²

→ Take √ for both sides

∴ x = 2

→ Substitute x in the expressions of leg1 and leg2 to find them

∴ leg1 = 2(2) = 4 inches

∴ leg2 = 3(2) = 6 inches

∵ hypotenuse = \sqrt{(leg1)^{2}+(leg2)^{2}}

∴ hypotenuse = \sqrt{(4)^{2}+(6)^{2}}=\sqrt{16+36}=\sqrt{52}

∵ The simplest form of \sqrt{52} = 2\sqrt{13}

∴ The length of the hypotenuse = 2\sqrt{13} inches

3 0
3 years ago
Solve 3x^2 + 6x+15=0
Elden [556K]

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, x =  \frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}

Or, x = \frac{\sqrt{-144} }{6}

∴   x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )  Answer

6 0
3 years ago
At one​ store, Julia saved ​$10 with a coupon for 40​% off her total purchase. At another​ store, the ​$29 she spent on books is
barxatty [35]
Let "a" and "b" represent the values of the first and second purchases, respectively.
  0.40*(original price of "a") = $10
  (original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
  a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
  a = $25.00 -10.00 = $15.00

At the other store,
  $29 = 0.58b
  $29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate

Then Julia's total spending is
  a + b = $15.00 +50.00 = $65.00

Julia spent $65 in all at the two stores.
6 0
3 years ago
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