1 5/8
1 7/8 - 2/8= 8+7/8 - 2/8= 15/8 - 2/8= 13/8=
1 5/8 is the answer
This is a basic addition/subtraction question. It's saying that they started at the 50 yard line. On the play, they gained 7 yards. So, we'll add 50+7 = 57.
They're at the 57 yard line at this point. On the second play they lost 10 yards (how unfortunate). Thereby, we will subtract 57-10=47.
50 yards +7 yards. -10 yards.
The answer will be that they'll be on the 47 yard line on the next play.
Answer:
h(x) = 3(x - 5)^2 + 6.
Step-by-step explanation:
g(x) = 3x^2 + 8
Shifting 5 units to the right gives:
3(x - 5)^2 + 8
Now 2 units down :
3(x - 5)^2 + 8 - 2
= 3(x - 5)^2 + 6.
Answer : 4 times
Here it's given that ,
- The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .
And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .
Let us take ,
- base of blue butterfly be b
- height of blue butterfly be h
- Area be A .
Then ,
- base of red butterfly will be 2b .
- height of red butterfly will be 2h .
- Area be A' .
We know that ,
→ area of the triangle = 1/2 × base × height
So that ,
→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)
→ A/A' = bh/4bh
→ A/A' = 1/4
→ A' = 4A
<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>
I hope this helps.
