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Dennis_Churaev [7]
3 years ago
12

Which set of ratios could be used to determine if one triangle is a dilation of the other

Mathematics
1 answer:
Lisa [10]3 years ago
3 0

Answer:

See explanation

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

Step-by-step explanation:

The two triangles are similar if the ratio of the corresponding sides are proportional.

The ratio of the corresponding sides are:

\frac{3.6}{3}  = 1.2

\frac{5.4}{4.5}  = 1.2

\frac{6}{5}  = 1.2

The set of ratios which could be used to determine if one triangle is a dilation of the other is

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

If there are multiple correct options then check this one too.

\frac{3}{3.6}  =  \frac{4.5}{5.4} =  \frac{5}{6}

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Which statement describes the behavior of the function f (x) = 3x/4-x
Luba_88 [7]

The graph approaches 0 as x approaches infinity.

Step-by-step explanation:

The behavior of the graph is presented by the function;

f(x)= 3x/4-x

Forming a table to see the behavior,

x          f(x)

1            1

2            3

3            9

4             infinity

5             -15

6              -9

7             -7

8             -6

This shows that as value of x approaches positive infinity, the value of f(x) approaches 0.

Learn More

Functions :brainly.com/question/11275875

Keywords : statements, behavior, function, graph

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8 0
3 years ago
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Point A is located at (-4,\ 9)(−4, 9) on the coordinate plane. Point B is located at (-4,\ -7)(−4, −7). ​What is the distance be
galben [10]

Answer:

AB = 16 units

Step-by-step explanation:

Given the coordinate (-4, 9) and (-4, -7)

Using the formula for calculating the distance between two points

AB = √(x2-x1)²+(y2-y1)²

AB =√(-7-9)²+(-4+4)²

AB = √(-16)²+0²

AB = √16²

AB = 16 units

Hence the distance between Point A and Point B is 16 units

8 0
3 years ago
Find the area enclosed by the graphs of x + y = 6 , x − y = 0 , y + 5x = 6 .
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6 0
3 years ago
A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses
mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for x days.

So, for x days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = \frac{360}{x}

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = (x+4) days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= (\frac{360}{x}-3)

Total expense in dollars can now be given as:  (x+4)(\frac{360}{x}-3)

Simplifying by using distribution (FOIL).

(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))

360-3x+\frac{1440}{x}-12

348-3x+\frac{1440}{x}

We know total expense remains the same which is = $360.

So, we have the equation as:

348-3x+\frac{1440}{x}=360

Multiplying each term with x to remove fractions.

348x-3x^2+1440=360x

Subtracting 348x both sides

348x-348x-3x^2+1440=360x-348x

-3x^2+1440=12x

Dividing each term with -3.

\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}

x^2-480=-4x

Adding 4x both sides.

x^2+4x-480=-4x+4x

x^2+4x-480=0

Solving using quadratic formula.

For a quadratic equation: ax^2+bx+c=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plugging in values from the equation we got.

x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}

x=\frac{-4\pm\sqrt{16+1920}}{2}

x=\frac{-4\pm\sqrt{1936}}{2}

x=\frac{-4\pm44}{2}

So, we have

x=\frac{-4+44}{2}   and x=\frac{-4-44}{2}

x=\frac{40}{2}   and x=\frac{-48}{2}

∴ x=20           and x=-24

Since number of days cannot be negative, so we take x=20 as the solution for the equation.

Thus, the original duration of the tour = 20 days

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How do you do percentages?​
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https://www.skillsyouneed.com/num/percent-change.html

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