<h3>Answer: Radius</h3>
Let point A be the center of the circle. Point B is somewhere on the circle edge. The distance from A to B is equal to the radius. The radius is half the diameter which spans the whole circle and it goes through the center. The circumference is the curved distance around the whole circle's perimeter.
Answer:
Step-by-step explanation:
GIVEN THAT,
LET'S SOLVE NOW
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9514 1404 393
Answer:
- ABHGEFDCA
- does not exist
- ECBADFE
Step-by-step explanation:
A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.
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For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.
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For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.
Its a translation otherwise known as a slide
