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KatRina [158]
3 years ago
12

If the crate took 8 seconds to go from traveling at 2 meters per second one way to moving at 2 meters per second in the opposite

direction, what is its acceleration?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

-0.5 ms^-2

Step-by-step explanation:

The initial velocity (u) = 2 ms-1

Final velocity (v) = 2 ms-1

Time taken (t) = 8 seconds

However the question clearly says that the final velocity is in opposite direction to the initial velocity. This implies that we have (-v), final velocity in opposite direction.

We must recall that vectors in opposite direction are commonly shown using a negative sign. Velocity is a vector, hence it possesses both magnitude and direction as we can see from the question.

Hence;

From a= v-u/t

a= (-2) - 2 / 8 = -0.5 ms^-2

Hence the acceleration of the crate is -0.5 ms^-2

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oee [108]
The answer I believe is 5 because 2 vases hold 10 red roses and 5 yellow roses. But since the person has 3 vases but it has to be the same amount as the first person. They would both have 30 flowers in their vases. But then each of the vases has 6 red roses so you just do 30 divided by 6 and you get 5.
4 0
3 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
M=0.75d - 2 proportional or non proportional?
ArbitrLikvidat [17]

Answer:

Non proportional

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Debora [2.8K]

Yo sup??

you can solve this quesion by having the knowledge of trigonometric ratios

let angle B be x, then

tanx=7/3

x=66.8

Hope this helps

4 0
3 years ago
I have 30 photos to post on my website. I'm planning to post these on two web pages, one marked "Friends" and the other marked "
Sergio039 [100]

Answer:a) 870

b) 435

Step-by-step explanation:

a)

number of photos to be posted =n = 30

number of web pages on which they would be posted is 2

Since the order in which the photos appear on the web pages matters,

Number of ways = 30 permutation 2

=870 ways

b)

Since the order in which the photos appear on the web pages does not matter,

Number of ways = 30 combination 2

= 435 ways

6 0
3 years ago
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