≥The solution of an inequality is an interval, i.e. a range.
To prove that the interval found as solution, you must consider several cases.
1) In the case that the ineguailty is ≥ or ≤, first use the limits of the interval to prove they are valid solutions. This is, replace the limit values, one at a time, and verifiy the inequality.
2) If the sign is ≥ or > use a value to the right of the limit value to show that the values to the right are solution, and use a value to the left to show that they are not solution.
3) If the sign is ≤ or <, use a value to the left of the limit value to show that it is a solution and a value to the right of the limit value to show that it is not a solution.
What's the problem but here's how to do one
hope I answered your questions
Answer:ges
Step-by-step explanation:
The surface area of a cylinder with circular bases of radius <em>r</em> and height <em>h</em> is equal to the sum of the areas of the two circular faces and the area of the rectangular lateral surface:
<em>A</em> = 2π<em>r</em>² + 2π<em>rh</em>
If you know the height <em>h</em>, then you can solve the quadratic equation for <em>r</em>.
The answer will be multiple times wich the number needs to change
