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kati45 [8]
3 years ago
13

Use complete sentences to describe the process in proving that the solution of an inequality is valid.

Mathematics
1 answer:
saul85 [17]3 years ago
7 0
≥The solution of an inequality is an interval, i.e. a range.

To prove that the interval found as solution, you must consider several cases.

1) In the case that the ineguailty is ≥ or ≤, first use the limits of the interval to prove they are valid solutions. This is, replace the limit values, one at a time, and verifiy the inequality.

2) If the sign is ≥ or > use a value to the right of the limit value to show that the values to the right are solution, and use a value to the left to show that they are not solution.

3) If the sign is ≤ or <, use a value to the left of the limit value to show that it is a solution and a value to the right of the limit value to show that it is not a solution. 
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if the cost of a dress is multiplied by 5/8 the price then becomes $30.00 what was the original price
Alik [6]
Let's label the original price of the dress as x. We know that
x \times  \frac{5}{8}  = 30
so that means that we can find x by dividing both sides by 5/8:
x = 30   \div  \frac{5}{8}
A simple rule for dividing fractions is 'Keep Change Flip'. You keep the first number/fraction the same, you change the ÷ to a × and you flip the second fraction. Through this rule, we can now solve the equation much more easily:
x = 30 \times  \frac{8}{5}  \\ x =  \frac{240}{5} \\ x = 48
Therefore, the original price of the dress was $48
6 0
4 years ago
Kinda forgot how to do this but i got 894.09 for my answer not sure if im right
Andreas93 [3]
You correct the answer is 894.09
7 0
3 years ago
PLEASE HELP ME!!!! THANK YOU SO SO SO MUCH.
polet [3.4K]
It would be A because everything is doubled
4 0
4 years ago
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PLSS HELP ILL GIVE A BRAINLIEST TO WHOEVER IS RIGHT
maks197457 [2]
Answer is Use math paa :))))))
4 0
3 years ago
Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give
Aloiza [94]

Answer:

y = 4e^2x - 3e^2  

Step-by-step explanation:

f(x) = e^{2x^2}

lets calculate the derivate of f using the chain rule:

f'(x) = e^{2x^2}* (2x^2)' = e^{2x^2}*4x = 4e^{2x^2}x

we have that f'(1) = 4e^2, hence the equation is

y = f(1) + f'(1) (x-1) = e^2 + 4e^2(x-1)

or, equivalently,

y = 4e^2x - 3e^2  

4 0
3 years ago
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