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LUCKY_DIMON [66]
3 years ago
10

4+2i/2−i solve for this expression​

Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer: \frac{6+8i}{5} or \frac{6}{5}+\frac{8i}{5}

Step-by-step explanation:

Multiply the numerator and denominator of \frac{4+2i}{2-i} by the conjugate of  2-i to make the denominator real.

\frac{4+2i}{2-i}*\frac{2+i}{2+i}

Multiply using the distributive property (foil method)

\frac{6+8i}{5}

Answer: \frac{6+8i}{5} or \frac{6}{5}+\frac{8i}{5}

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I need help please and thank you
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3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0
3 years ago
A courier originally had 5 packages to deliver. Suppose x represents the number of packages she has delivered so far and y repre
Olenka [21]

Answer:

A,E,F

Step-by-step explanation:

5 0
2 years ago
KLM is isosceles. Calculate the segment EF from the data in the drawing. <br><br><br> HELP!!
Arte-miy333 [17]

Answer:

4.5 cm

Step-by-step explanation:

KL = LM as triangle is isosceles

LM = KM as LF = FM = KN = NM, so the triangle is equilateral

EF ║ NM as LE⊥EF and LN⊥NM

EF is half the midsegment as ∠KLN ≅ ∠MLN, and LN is angle bisector of ∠KLM

Midsegment is half the side length, and all sides are 18 cm.

EF = 1/2(1/2*18) = 4.5 cm

5 0
3 years ago
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