Which graph best represents the equation 12x+6y=0?

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Black_prince [1.1K]

Answer:

C

Step-by-step explanation:

A and B would be very expensive for 2 people, and D is too little, so C would be sensible! Hope this helps!

5 0

2 years ago

Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156 and interest if

aleksley [76]

Answer:

6%.

Step-by-step explanation:

We have been given that Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156.

To find the interest rate we will use simple interest formula.

$I=P*r*T$

I= Interest.

P= Principal amount.

r=Annual interest rate (in decimal form).

T= Time in years.

We have been given that I=156, T=5, P=520

Upon substituting our values in above formula we will get,

$156=520*r*5$

$156=2600r$

$r=\frac{156}{2600}$

$r=0.06$

Let us multiply 0.06 by 100 to convert annual interest rate in percentage.

$0.06*100=6 \text{ percent}$

Therefore, the annual interest rate was 6%.

6 0

4 years ago

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

3 years ago

(PLEASE HELP ME)(I WILL GIVE YOU BRAINLINEST)Suppose homes in a big city increase in value 13% every year. How much will a home

kolbaska11 [484]

Answer:

$216435

Step-by-step explanation:

Given : Suppose homes in a big city increase in value 13% every year.

To Find: How much will a home that cost $150,000 be worth 3 years later?

Solution:

Principal = $150000

Rate = 13% =0.13

Time = 3 years

Formula : $A=P(1+r)^t$

Now substitute the values in the formula

$A=150000(1+0.13)^3$

$A=216434.55$

So, The cost of home after 3 years will be $216435

Hence Option B is true

3 0

3 years ago

Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.

sweet [91]

Answer:

None

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

4 0

3 years ago

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