Which graph best represents the equation 12x+6y=0?

PLEASE HELP ME!

Gekata [30.6K]

Answer:

He'll have $195 left

Step-by-step explanation:

$35 x 3 = $105

$300 - $105 = $195

6 0

3 years ago

Read 2 more answers

Ten of 16 students in Nyack's class are girls. His teacher selected two

viktelen [127]

I can't understand this after "happening is" but let's do it unaided.

The number of ways to draw a boy first is 6.

Given that, the number of ways to draw a girl next is 10.

That's out of a total of 16 x 15 length two permutations of 16 things

$p = \dfrac{6 \times 10}{16(15)} = 1/4$

Answer: 1/4

7 0

3 years ago

This is Adele’s solution for the equation.

Mkey [24]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: She messed up in Step 1

She first should of tried to factor it first. There she can see that 3 and -11 work together in order to get (x+3)(x-11)

x= -3 and x=11

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

5 0

2 years ago

Read 2 more answers

Ruben earns $4 an hour as a cashier and $5.50 and hour as a waiter. If he works 5 days per week, how much does he earn if he wor

34kurt

So to find how much Ruben will make if he works 4 hours a day as a cashier and 3 hours a day as a waiter for 5 days per week first we'll work on his cashier job. So he makes 4$ an hour as a cashier and her works 4 hours every day for 5 days, multiply 4 by 4 and you'll get 16, so he makes 16 dollars per day as a cashier. now that we know how much he makes a day we simply have to multiply 16 by 5 since he works for 5 days every week. 16*5 is 80, so Ruben makes 80 dollars working 4 hours a day for 5 days. Now we move onto his waiter job. he makes 5.50 an hour as a waiter and her works 3 hours a day. So we multiply 3 by 5.50 to get 16.5. Next, we multiply 16.5 by 5 since he also works 5 days a week as a waiter. 16.5*5 is equal to 82.5. now we add 82.5 and 80 to get 162.5. SO Ruben makes 162.5$ working both jobs 5 days a week

7 0

2 years ago

1. Find a vector in R^3 which is not in the span of the set S-((1,2, -2), (2, -1, 1). Explain.

pav-90 [236]

Answer:

Step-by-step explanation:

A vector in R^3 which is not in the span of the set S {(1,2,-2) and (2,-1,1)

If a vector is in the span it can be represented as a linear combination of these two vectors

Let S1 = (1,2,-2) and S2 = (2,-1,1)

i.e. any vector which is of the form

$\alpha S1+\beta S2\\=(\alpha +2\beta,2\alpha -\beta,-2\alpha +\beta)$

Where alpha and beta are any real numbers

Any vector not in this form will not be in the span

i.e. say if alpha = beta =1,

then spanned vector = (3,1,-1)

If we change one coordinate alone say

(3,0,-1) this cannot be represented as a linear combination hence this would be the answer.

8 0

3 years ago