Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose
We have 
and 
, because the dice are fair.
Now we use the assumption of independence to claim that
Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of 
are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5
A = 2w+5
example: on week three, she would have the recipes from the other weeks that you have to account for as well as the extra five
2(3)+5=11 so A would equal 11 by week three.
Use multiplication because it is essentially repeated addition.
2(from week 1) + 2(from week 2) + 2(from week 3) + 5(prior to school) =11
There are 3 egg rolls divide evenly to 8 sisters
for 1 egg roll each sister would receive 1/8 since there are 3 egg rolls
multiply 1/8 x 3
each sister will get 3/8 of an egg roll
hope this helps
