Answer:
x²+5x - 150 = 0
Step-by-step explanation:
Let the length be y and width be x
If the length of a swimming pool is 10 more than 2 times the width, then;
y = 2x+10 ...1
Since the Area is 300m²
A = xy
300 = xy .... 2
Substitute 1 into 2
300 = x(2x+10)
300 = 2x²+10x
Rearrange
2x²+10x - 300 = 0
Divide through by 2
x²+5x - 150 = 0
This gives the required quadratic expression
Sin A = 56/75
A = sin^-1 (56/75) = 48.30 degrees
Step-by-step explanation:
Its the bottom question sir
Answer:
time = 1secs
<em>Max height = 25metres</em>
Step-by-step explanation:
Let the equation that models the height of the ball be expressed as;
h(t) = −16t^2 + 32t + 9
t is the time in seconds
The velocity of the ball at its maximum height is zero i.e dh/dt = 0
dh/dt = -32t + 32
0 = -32t + 32
32t = 32
t = 32/32
t = 1 seconds
The ball will reach its maximum height after 1 seconds.
Get the maximum height reached. Substitute t = 1 into the modeled function;
h(t) = −16t^2 + 32t + 9
h(1) = −16(1)^2 + 32(1) + 9
h(1) = −16 + 32 + 9
h(1)= 16+9
<em>h(1) = 25</em>
<em>Hence the maximum height reached is 25metres</em>
In terms of "ratio units," the length of AC is 3+7=10, so each one is worth 120/10 = 12. The length BC is 7 of those, or 7·12 = 84.