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EleoNora [17]
3 years ago
7

What is the measure of angle A to the nearest degree

Mathematics
2 answers:
ipn [44]3 years ago
7 0
Sin A = 56/75
A = sin^-1 (56/75) = 48.30 degrees
Archy [21]3 years ago
4 0

Answer:

A\approx 48^o

Step-by-step explanation:

We have been given an image of a right triangle and we are asked to find the measure of angle A of our given triangle.

We can see that hypotenuse and opposite side to angle A is given. Since sine represents the relation between opposite and hypotenuse of a right triangle, so we will use sine to find the measure of angle A.

\text{Sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

Upon substituting our given values in above relation we will get,

\text{Sin A}=\frac{56}{75}

A=\text{Sin}^{-1}(\frac{56}{75})

A=48.302453396837^o

Upon rounding our answer to nearest degree we will get,

A\approx 48^o

Therefore, the measure of angle A to the nearest degree is 48 degrees.

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Solve the expression x^2-100=0
enot [183]

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± \sqrt{100} ← note plus or minus, hence

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6 0
3 years ago
Please help this is so confusing
AURORKA [14]

Answer:

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Step-by-step explanation:

Translation involves the movement of a triangle without changing its direction or shape. It basically involves the sliding of a triangle, so Triangle 2 satisfies the definition of translation.

6 0
3 years ago
Please need help to solve this
Sunny_sXe [5.5K]
Greetings!

Convert both terms into improper fractions:
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The second answer would be correct.

Hope this helps.
-Benjamin
5 0
3 years ago
5m - n + 7 - 4m +6n help
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Answer:

m+5n+7

Step-by-step explanation:

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=5m-4m-n+6n+7

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4 0
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A supervisor records the repair cost for 23 randomly selected stereos. A sample mean of $91.82 and standard deviation of $16.84
Assoli18 [71]

Answer: 2.508

Step-by-step explanation:

As per give , we have

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significance level : \alpha: 1-0.98=0.02

Since , the sample size is small (n<30) and population standard deviation is unknown.

So , we use t-test.

For confidence interval , we find two-tailed test value.

Critical t-value : t_{\alpha/2, df}=t_{0.01,22}

=2.508  [using students's t-critical value table]

Hence, the critical value that should be used in constructing the confidence interval = 2.508

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