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bulgar [2K]
3 years ago
9

Triangle A B C is reflected across the line of reflection m to form triangle A prime B prime C prime. Triangle A prime B prime C

prime is doubled in size to form triangle A double-prime B double-prime C double-prime.
Kyla applied rm ◦ T0,3 to triangle ABC. What mistakes did she make? Check all that apply.

She applied the rotation to the triangle first.
She applied the reflection to the triangle first.
She changed the size of the triangle instead of just applying a translation.
She translated the triangle down instead of just applying a reflection.
She applied a rotation instead of a reflection.
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
5 0

Answer:

The correct answers are the following:

B. She applied the reflection to the triangle first.

C. She changed the size of the triangle instead of just applying a translation.

Step-by-step explanation:

Edge 2020

Hope this helped!

Anna11 [10]3 years ago
3 0

Answer:

its B and C

llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll

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\displaystyle \displaystyle \int {sin(3x)} \, dx = \frac{-cos(3x)}{3} + C

General Formulas and Concepts:

<u>Calculus</u>

Antiderivatives - Integrals

Integration Constant C

Integration Property [Multiplied Constant]: \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration: \displaystyle \int{sin(x)} \, dx = -cos(x) + C

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \int {sin(3x)} \, dx

<u>Step 2: Identify Substitution Variables</u>

u = 3x

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<u>Step 3: Integrate</u>

  1. [Integral] Rewrite:                                                                                           \displaystyle \frac{1}{3}\int {3sin(3x)} \, dx
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  5. [Expression] Back-Substitute:                                                                        \displaystyle \frac{-cos(3x)}{3} + C
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sp2606 [1]

Answer:

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Step-by-step explanation:

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