Zero of 7 with a multiplicity of 3 means one factor is 
Zero of -1 with a multiplicity of 2 means one factor is 
Zero of 5 with a multiplicity of 1 means one factor is 
Multiplying, we get

That's already in factored form so we leave it here.
To get you answer multiply the length and width twice. Then the length and height twice. Then the width and height twice. And add it all up.
7* 1.25= 8.75
7* 1.25= 8.75
7*6.5= 45.5
7*6.5= 45.5
6.5*1.25=8.125
6.5*1.25=8.125
Answer:
Step-by-step explanation:
(edit):
lol this post was an accident, mb
<h3>
Answer: 80 degrees</h3>
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Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
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Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
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Here's what we have so far for quadrilateral DAEC
- angle A = 90
- angle E = 100
- angle C = 90
- angle D = unknown
Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.
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