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Kryger [21]
3 years ago
12

Which trinomial is the product of the expression below ? (2R-3) (R+12)

Mathematics
2 answers:
anastassius [24]3 years ago
8 0
Answer:
2R^2 + 21R - 36

Explanation:
To answer this question, we will follow these steps:
1- expand the brackets
2- gather like terms

Steps are as follows:
(2R-3)(R+12) = 2R(R) + 2R(12) - 3(R) - 3(12)
                      = 2R^2 + 24R - 3R - 36
                      = 2R^2 + 21R - 36

Hope this helps :)

Nostrana [21]3 years ago
7 0
We have that

(2R-3) (R+12)---------- > 2R*R+12*2R-3*R-3*12---------- > 2R²+24R-3R-36

2R²+24R-3R-36---------------> 2R²+21R-36

the answer is 2R²+21R-36
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Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD                 (Given)

\angle ADC\cong \angle ACD

m\angle ADC=m\angle ACD

According to the angle sum property, the sum of interior angles of a triangle is 180°.

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Divide both sides by 2.

m\angle ACD=68

CE bisects ∠ACD.

m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}

m\angle ACE=m\angle DCE=\dfrac{68}{2}

m\angle ACE=m\angle DCE=34

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m\angle CDE+m\angle DCE+m\angle DEC=180

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Subtract 102 from both sides.

m\angle DEC=180-102

m\angle DEC=78

Therefore, the measure of angle DEC is 78°.

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