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3 years ago

Which trinomial is the product of the expression below ? (2R-3) (R+12)

2 answers:

8 0

Answer:
2R^2 + 21R - 36

Explanation:
To answer this question, we will follow these steps:
1- expand the brackets
2- gather like terms

Steps are as follows:
(2R-3)(R+12) = 2R(R) + 2R(12) - 3(R) - 3(12)
= 2R^2 + 24R - 3R - 36
= 2R^2 + 21R - 36

Hope this helps :)

Nostrana [21]3 years ago

7 0

We have that

(2R-3) (R+12)---------- > 2R*R+12*2R-3*R-3*12---------- > 2R²+24R-3R-36

2R²+24R-3R-36---------------> 2R²+21R-36

the answer is 2R²+21R-36

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3 years ago

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4=dcba. The digits a, b,

Arisa [49]

The given is that A B C D x 4 = D C B A

Possible values of A are 1 or 2. It can't be 1 since the final result A is in unit place and 1 is not possible when we multiply any number by 4

2 B C D x 4 = D C B 2
It is clear above, that D = 8
2 B C 8 x 4 = 8 C B 2
Possible values of B should be 1 or 2
We try B=1

2 1 C 8 x 4 = 8 C 1 2

To find for C, you can use the equation:

(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,

C = 7
So, the number is 2178.

5 0

3 years ago

Read 2 more answers

Please explain to me how to solve this problem and what would be the correct answer answer asap!!!

hodyreva [135]

Given
f(x)= -3x - 5
g(x)= 4x - 2

Find
(f - g)(x)
substitute the f and g values in (f - g)

(f - g)(x)= -3x - 5 - (4x - 2)
change the signs in parentheses because there is a negative sign in front of the parentheses

(f - g)(x)= -3x - 5 - 4x + 2
combine like terms

(f - g)(x)= -7x - 3

ANSWER: (f - g)(x)= -7x - 3

Hope this helps! :)

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3 years ago