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Kryger [21]
3 years ago
12

Which trinomial is the product of the expression below ? (2R-3) (R+12)

Mathematics
2 answers:
anastassius [24]3 years ago
8 0
Answer:
2R^2 + 21R - 36

Explanation:
To answer this question, we will follow these steps:
1- expand the brackets
2- gather like terms

Steps are as follows:
(2R-3)(R+12) = 2R(R) + 2R(12) - 3(R) - 3(12)
                      = 2R^2 + 24R - 3R - 36
                      = 2R^2 + 21R - 36

Hope this helps :)

Nostrana [21]3 years ago
7 0
We have that

(2R-3) (R+12)---------- > 2R*R+12*2R-3*R-3*12---------- > 2R²+24R-3R-36

2R²+24R-3R-36---------------> 2R²+21R-36

the answer is 2R²+21R-36
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3 years ago
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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

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The values of \sin 2x, \cos 2x, \tan 2x.

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It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

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Now,

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And,

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\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

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We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

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7 0
2 years ago
If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4=dcba. The digits a, b,
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The given is that A B C D <span>x 4 = D C B A
</span><span>
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</span><span>
2 B C D x </span><span>4 = </span><span>D C B 2</span>
It is clear above, that D = 8
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5 0
3 years ago
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Please explain to me how to solve this problem and what would be the correct answer answer asap!!!
hodyreva [135]
Given
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Find
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substitute the f and g values in (f - g)

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(f - g)(x)= -3x - 5 - 4x + 2
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ANSWER: (f - g)(x)= -7x - 3

Hope this helps! :)
5 0
3 years ago
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