C. 50 I believe. Because it has to be equal to 180 making 2 different angles together to get 180. If that makes sense
y^2 = x isn't a function because there is at least one value of x that produces multiple values of y. In fact, any x value greater than 0 yields two y values. If x = 0, then y = 0 is the only solution. ... Graphically, the equation fails the vertical line test, which is another way to determine that it is not a function.
Answer:
The inverse of the function is
.
Step-by-step explanation:
The function provided is:

Let
.
Then the value of <em>x</em> is:

For the inverse of the function,
.
⇒ 
Compute the value of
as follows:
![f[f^{-1}(x)]=f[\frac{x-5}{3}]](https://tex.z-dn.net/?f=f%5Bf%5E%7B-1%7D%28x%29%5D%3Df%5B%5Cfrac%7Bx-5%7D%7B3%7D%5D)
![=3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x](https://tex.z-dn.net/?f=%3D3%5B%5Cfrac%7Bx-5%7D%7B3%7D%5D%2B5%5C%5C%5C%5C%3Dx-5%2B5%5C%5C%5C%5C%3Dx)
Hence proved that
.
Compute the value of
as follows:
![f^{-1}[f(x)]=f^{-1}[3x+5]](https://tex.z-dn.net/?f=f%5E%7B-1%7D%5Bf%28x%29%5D%3Df%5E%7B-1%7D%5B3x%2B5%5D)

Hence proved that
.
Answer: the length of string that been let out to fly the kite this high is 172.89 ft
Step-by-step explanation:
The length of string attached to the kite, the vertical height of the kite above the ground and the ground distance forms a right angle triangle.
With an angle of 57 degrees, the length of the string that is attached to the kite represents the hypotenuse of the right angle triangle.
The height of the kite above the ground represents the opposite side of the triangle
To determine h, the length of the string that has been let out to fly the kite this high, we would apply the
Sine trigonometric ratio which is expressed as
Sine θ = opposite side/hypotenuse
Sin 57 = 145/h
h = 145/Sin57 = 145/0.8387
h = 172.89
if x equals 100 then the answer will be 100 because if you multiply 100 by 3 you will get 300