Answer:
The value of ROE that will be exceeded by 78% of the firms is -1.77%.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The mean ROE for the firms studied was 14.93% and the standard deviation was 21.74%. This means that 
What value of ROE will be exceeded by 78% of the firms?
This is the value of X when Z has a pvalue of 1-0.78 = 0.22.
This is 
So:
The value of ROE that will be exceeded by 78% of the firms is -1.77%.
Answer: Last one is right C = 5 / 9 (F-32)
Step-by-step explanation: Solving C from equation F = (9/5)C + 32 :
1. multiply by 5 you get 5F = 9C + 160 and 5(F-32) = 9C
2. divide by 9 you get (5/9) (F-32) = C
Answer:
Landing on a 1 or 2.
25% means 0.25, or 2/8 chance of winning. The spinner has 2 out of 8 as 1 or 2.
Answer:
The answer is 54
Step-by-step explanation:
36+90=126
180-126= 54
Answer:
.b. It is one‐half as large as when n = 100.
Step-by-step explanation:
Given that a simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.
i.e. s = 0.3
we obtain se of sample by dividing std devitation by the square root of sample size
i.e. s= 
when n =100 this = 0.3 and
when n =400 this equals 0.15
We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original
Correction option is
.b. It is one‐half as large as when n = 100.
