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Nutka1998 [239]
3 years ago
9

Given the function defined in the table below, find the average rate of

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

Average rate of change = \frac{2}{5}

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = \frac{32-14}{65-20}

                                        = \frac{18}{45}

                                        = \frac{2}{5}

Therefore, average rate of change in the given interval is \frac{2}{5} .

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Which is greater, 1 5/8 or 1 2/3 how can you be sure?
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Lets get these into improper fractions. 

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h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]

Answer:

1

Step-by-step explanation:

If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

A function for the rate of change of G(t) is given by G'(t).

G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2

G'(t) = -2t + 2

This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.

So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0
3 years ago
Anyone help with these 2 question?
ICE Princess25 [194]

Step-by-step explanation:

1.√2×(-2√9)×(-√2)

= -2×(-2×3)

=12 option a

2. √5×√15×√75

= √5×(√3√5)×(5√3)

= 5×3×5

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3 years ago
I need help!!!!!!!!!!!!
qaws [65]

When I do what the problem statement says, I get 47° for the left angle and 58° for the right one. They are not congruent.

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3 years ago
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