Lets get these into improper fractions. 
1*8 + 5 = 8+5 = 13
13/8 
1*3 + 2 = 3+2 = 5
5/3
Now divide
13/8 = 1.625
5/3 = 1.6666
1  2/3 is larger 
        
                    
             
        
        
            
            
                h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu 
                lesya692 [45]             
         
        
Answer:
1
Step-by-step explanation:
If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.
A function for the rate of change of G(t) is given by G'(t).
G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.
d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2
G'(t) = -2t + 2
This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.
So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1
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Step-by-step explanation:
1.√2×(-2√9)×(-√2)
= -2×(-2×3)
=12 option a
2. √5×√15×√75
= √5×(√3√5)×(5√3)
= 5×3×5
=75 option b
 
        
             
        
        
        
When I do what the problem statement says, I get 47° for the left angle and 58° for the right one. They are not congruent.