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Sloan [31]
3 years ago
10

How much would your 20.0 kg dog weigh on Neptune?

Physics
2 answers:
Agata [3.3K]3 years ago
7 0
F= 6m.m2/r^2

F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2


ANS: F= 260 N=2.60x10^2 N
Ipatiy [6.2K]3 years ago
4 0

Answer:

W=223 N

Explanation:

To know the weight of a person,an animal or an object we have the equation:

W=mg

Where:

<em>W: Weight of the person, animal or object.</em>

<em>m: Mass of the person, animal or object.</em>

<em>g: Acceleration of gravity.</em>

In this case we know the mass of the dog m=20.0kg, then in order to find the Weight we need to  know g, the acceleration of gravity, in case of the Earth g=9.8\frac{m}{s^{2} }, but on Neptune g has another value.

g_{n} =11.15\frac{m}{s^{2} }, where g_{n} is the acceleration of gravity on Neptune.

Now, replacing the data:

<h2>W=mg\\ W=20.0kg(11.15\frac{m}{s^{2} } )\\ W=223.0 kg\frac{m}{s^{2} } \\ W=223.0 N</h2>
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a cheerleader throws herself into the air with a velocity of 12 m/s at an angle of 75 degrees above the horizontal. what are the
NISA [10]

Answer:

Vx = 3.10 [m/s]

Vy = 11.59 [m/s]

Explanation:

To solve this problem we must decompose the velocity vector by means of the angle on the horizontal.

v = 12 [m/s]

Vx = 12*cos (75) = 3.10 [m/s]

Vy = 12*sin (75) = 11.59 [m/s]

7 0
4 years ago
Explain whether Washington, D.C., or
Svetradugi [14.3K]
I would say Orlando since its near more ocean than Washington. Since Ocean can change weather by making it cold or warm depending on the season.
5 0
3 years ago
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An archer shoots an arrow into a target using a bow. If the "action" force is the force of the bowstring against the arrow, what
aliya0001 [1]
Weight of an arrow is 20 plus 3
8 0
3 years ago
A ballistic pendulum is a device used to measure the speed of a projectile, such as a bullet. The projectile, of mass m, is fire
aliina [53]

Answer:

v = ((m + M) / m)*√(2*g*h)

Explanation:

Given

m = mass of the projectile

M = mass of the ballistic pendulum

v = initial speed of the projectile

v' = speedof the system (pendulum + projectile) after the inelastic collision

h = maximum height reached for the system

Knowing that is an inelastic collision we have

m*v + M*(0) = (m+M)*v'

⇒  v' = m*v / (m+M)

After the collision, we apply the Principle of the Conservation of Energy

Ki + Ui = Kf + Uf

where

Ui = Kf = 0 J

then

Ki = Uf

0.5*(m+M)*v'² = (m+M)*g*h

⇒ 0.5*v'² = g*h

⇒ v'² = 2*g*h

⇒  (m*v / (m+M))² = 2*g*h

⇒  v = ((m+M) / m)*√(2*g*h)

7 0
3 years ago
A stone thrown horizontally from a height of 5.72 m hits the ground at a distance of 13.30 m. Calculate the initial speed of the
kakasveta [241]

Answer:

initial velocity=12.31 m/s

Final speed= 16.234 m/s

Explanation:

Given Data

height=5.72 m

distance=13.30 m

To Find

Initial Speed=?

Solution

Use the following equation to determine the time of the stone is falling.  

d = vi ×t   ½ ×9.8 × t²

Where  

d = 5.72m and vi = 0 m/s

so  

5.72 = ½× 9.8 ×t²

t = √(5.72 ÷ 4.9)

t=1.08 seconds

To determine the initial horizontal velocity use the following equation.

d = v×t

13.30 = v ×1.08

v = 13.30 ÷ 1.08

v=12.31 m/s

To determine stone’s final vertical velocity use the following equation

vf = vi+9.8×t............vi=0 m/s

vf = 9.8×1.08

vf= 10.584 m/s

To determine stone’s final speed use the following equation  

Final speed = √[Horizontal velocity²+Final vertical velocity²]

Final speed = √{(12.31 m/s)²+(10.584 m/s)²}

Final speed= 16.234 m/s

3 0
4 years ago
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