Question

How much would your 20.0 kg dog weigh on Neptune?

Answer 1

F= 6m.m2/r^2

F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2


ANS: F= 260 N=2.60x10^2 N

Answer 2

Answer:

W=223 N

Explanation:

To know the weight of a person,an animal or an object we have the equation:

W=mg

Where:

W: Weight of the person, animal or object.

m: Mass of the person, animal or object.

g: Acceleration of gravity.

In this case we know the mass of the dog m=20.0kg, then in order to find the Weight we need to  know g, the acceleration of gravity, in case of the Earth $g=9.8\frac{m}{s^{2} }$, but on Neptune g has another value.

$g_{n} =11.15\frac{m}{s^{2} }$, where $g_{n}$ is the acceleration of gravity on Neptune.

Now, replacing the data:

$W=mg\\ W=20.0kg(11.15\frac{m}{s^{2} } )\\ W=223.0 kg\frac{m}{s^{2} } \\ W=223.0 N$