Answer:
A) 3.48m/s
B) 3.92m
C) 2.32m
D 23.33m/s
Explanation:
ma(t)=mg-At
a(t)= g - (At/m)
V(t)= integrala(T)dT = gt- (At^2/2m)
Initial x coordinator of the box is zero
X(t)= integralV(t)dt= 1/2gt^2-(At^3/6m)
a) V =( 9.81×1) -(38×1^2/2×3)
V= 9.81-6.33= 3.48m/s
b)-AT^2/2m + gT= 0
T=2mg/A= (2×3×9.81)/38
T= 1.549m
X(T)= (1/2×9.81×1.549^3)- (38×1.549^3/6×3)
X(T)= 11.768- (141.23/18) = 11.768 - 7.85= 3.92m
C) 1/2gT''^2 - AT''^3/6m =0
The only non trivial solution is T''= 3mg/A
T=(3×3×9.81)/38 = 2.32m
D) V = 9.81×3) - (38×3^2/6)
V= 29 - 5.667= 23.33m/s
Answer:
b)7.89 g
c) 7.91 g
d) 7.97 g
Explanation:
The accepted value for the measurement is 7.92 g, while the precision of the instrument is 0.05 g. Therefore, the interval of the accepted values will be the central value plus and minus the precision, so:
- Minimum accepted value: 7.92 g - 0.05 g = 7.87 g
- Maximum accepted value: 7.92 g + 0.05 g = 7.97 g
So, the accepted interval is
7.87 g - 7.97 g
Therefore, all the values that lie within this interval are accepted. So the accepted values are:
b)7.89 g
c) 7.91 g
d) 7.97 g
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
<h3>What is image distance?</h3>
This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.
To calculate the image distance, we use the formula below.
Formula:
- 1/f = 1/u+1/v........... Equation 1
Where:
- f = Focal length of the mirror
- v = Image distance
- u = object distance
From the question,
Given:
Substitute these values into equation 1 and solve for the image distance
- 1/0.45 = 1/0.25 + 1/v
- 2.22 = 4+1/v
- 1/v = 2.22-4
- 1/v = -1.78
- v = 1/(-1.78)
- v = -0.56 m
Hence, The image distance is -0.56 m.
Learn more about image distance here: brainly.com/question/17273444
Answer:3W
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?
A) 2W
B) 3W
C) 4W
D) 6W
Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is
W = k(+q)(+q)/ d
k is couloumb's constant
work done in moving 3 equal positive charges from infinity to a finite distance is given by
W₂=W₄=W₆=k(+q)(+q)/ d
Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d
= W + W + W = 3W
Answer:
due to condection of heat from pan in thermal energy according to 9th
Explanation:
