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3 years ago

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5 milligrams into quintal

1 answer:

Greeley [361]3 years ago

4 0

Answer:

divide the mass value by 1e+8

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Using the equation zeff=z−s and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screen

DIA [1.3K]

Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help.

<span>Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 17- 10 =7 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 19- 10 = 9
</span>
S = 2 + 6.8 + 2.45 = 11.25
<span>Zeff(Cl^-) = 17 – 11.25 = 5.75 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence </span>
<span>Zeff(K^+) = 19 - 11.25 = 7.75</span>

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A sinewave has a period (duration of one cycle) of 645 μs (microseconds). What is the corresponding frequency of this sinewave,

Oliga [24]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

<u>Given the following data:</u>

Period = 645 μs

Note: μs represents microseconds.

<u>Conversion:</u>

1 μs = $1$ × $10^-6$ seconds

645 μs = $645$ × $10^-6$ seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

$Frequency = \frac{1}{Period}$

Substituting the value into the formula, we have;

$Frequency = \frac{1}{645 * 10^-6}$

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

<u>Conversion:</u>

1 hertz = 0.001 kilohertz

1550.39 hertz = X kilohertz

Cross-multiplying, we have;

X = $0.001$ × $1550.39$

X = 155039 kHz

To 3 significant figures;

<em>Frequency = 155 kHz</em>

Therefore, the corresponding frequency of this sinewave, in kHz is 155.

Find more information: brainly.com/question/23460034

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2 years ago