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Degger [83]
3 years ago
10

The charge on a parallel plate capacitor is 7.68 C, and the plate is connected to a 9.0 V battery. What is the capacitance of th

e capacitor?
A. 8.5x10^-7 pF
B. 1.1x10^-6 pF
C. 8.5x10^5 pF
D. 6.9x10^7 pF
Physics
1 answer:
Natali5045456 [20]3 years ago
8 0

Charge on a capacitor = (capacitance) x (voltage)

7.68 Coulomb = (capacitance) x (9.0 V)

Capacitance = (7.68 Coul) / (9.0 V)

<em>Capacitance = 0.83 Farad</em>

<em></em>

Apparently, the " 10^something " after the 7.68 C got lost.

If the charge is actually 7.68 <u>micro</u>coulombs, then the answer is<em> (A) .</em>

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