8 is in the tens place. It has a value of 80.
<span>let 2x be the length of rectangw where x is value of x of point on parabola width is represented as y is the length.
Area = 2x*y = 2x (5-x^2) = 10x -2x^3
maximize Area by finding x value where derivative is zero
dA/dx = 10 -6x^2 = 0
--> x = sqrt(5/3)
optimal dimensions: length = 2sqrt(5/3) width = 10/3</span>
Answer:
30+8%=C
Step-by-step explanation:
place the cost of the bag first then add the precent and make it equal to C wich is cost
