The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
Try rctanguular prism i think it is that
Answer:
Here you are. I hope this helps.
X=6 and x=1
You can find your zeros by determining what you have to plug into the function in order for it to equal zero
If we plug in 6, for example we’d get (6-6)(x-1)
Simplified this is 0(x-1)
Anything times 0 is 0, so this is one of our zeros.
Same goes for x-1, we just need to plug in 1 for it to equal 0
Therefore there are zeros at x=1 and x=6 :))
No because she can run slow and waste time and not get that far and it will be 3 min. But if you go fast and stop at the same distance it won’t take as long because of your SPEED.
