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Kay [80]
3 years ago
6

Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,

0, 0). (enter your answers as a comma-separated list of equations.)
Mathematics
1 answer:
wariber [46]3 years ago
7 0
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
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A rectangle has an area of 182 square meters and a base of 14 meters. What is the height?
katrin2010 [14]

Answer:

2488

Step-by-step explanation:

times 182 by 14 and it = 2488

5 0
3 years ago
Read 2 more answers
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
What number should be added to the expression x2 14x to change it into a perfect square trinomial?.
makkiz [27]

Answer:

  49

Step-by-step explanation:

When you look at the square of a binomial, you see ...

  (x +a)^2 = x^2 +(2a)x +a^2

The constant value (a^2) is <em>the square of half the x-coefficient</em>.

  (14/2)^2 = 49 . . . . the value to be added.

Adding 49 gives ...

  x^2 +14x +49 = (x +7)^2

8 0
2 years ago
Solve by using any method of substitution<br><br>4 +8x = y <br>6x - y = 2
Bumek [7]

Answer:

(-3,-20)

Step-by-step explanation:

4 +8x = y ...... equation (1)

6x - y = 2 ........equation(2)

from equation 2

6x - y = 2

6x -(4+8x) =2

6x - 4 + 8x = 2

    +4              +4

6x - 8x = 6

-2x=6

divide by -2

x= -3

put x in equation (1) to solve for y

4 + 8x = y

4+8(-3)=y

4-24=y

-20=y

y= -20

solution = (-3,-20)

8 0
3 years ago
Can someone please help me with this question about given two points?Please help ASAP!!! :(
KonstantinChe [14]

Answer:

<em>The order of subtraction is not important in any of the coordinates</em>

Step-by-step explanation:

Distance Between Two Points

Given two points (x1,y2) (x2,y2), the distance between them is given by the formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The difference between both coordinates is squared, then added, and finally extracted the square root.

Based on the principle that

a*a=a^2

and also

(-a)(-a)=a^2

We can notice it doesn't matter the sign of a the square of a is always positive. If we had subtracted in the opposite way, the distance would have resulted in exactly the same. In other words, the above formula is exactly the same as

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

As seen, it applies for both coordinates

6 0
3 years ago
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