The value would be 829.89.
The formula we use is

,
where A is the total amount, p is the principal, r is the rate expressed as a decimal number, n is the number of times per year the interest is compounded, and t is the number of years.
We will use 800 for p; 5.25/100 = 0.0525 for r; 365 for n; and (255/365) for t (since it is not a full year):
Hey!
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Steps To Solve:
4.6(x - 3) = -0.4x + 16.2
~Distributive property
4.6x - 13.8 = -0.4x + 16.2
~Add 0.4 to both sides
4.6x - 13.8 + 0.4= -0.4x + 16.2 + 0.4
~Simplify
5x - 13.8 = 16.2
~Add 13.8 to both sides
5x - 13.8 + 13.8 = 16.2 + 13.8
~Simplify
5x = 30
Divide 5 to both sides
5x/5 = 30/5
~Simplify
x = 6
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Answer:

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Hope This Helped! Good Luck!
Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So



has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.
Answer:
Is there multiple choice to this question?
anyway the answer maybe is: 0