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3 years ago

6

Which rational expression is equal to a positive whole number when evaluated?2 ^1/28 ^1/312 ^1/415 ^1/5

1 answer:

madreJ [45]3 years ago

3 0

<span>2 ^1/2
8 ^1/3 = (2³)^1/3 = 2
12 ^1/4
15 ^1/5

</span>

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Which graph shows a system of equations with no solutions?

podryga [215]

Graph of Parallel lines shows a system of equations with no solutions

Step-by-step explanation:

Consider a set of equations

$7x - 2y = 16\\21x + 6y =24$

If we solve this both equations using any one of the solving method, (Substitution method) then we will get

$7x-2y=16\\7x=16+2y\\x=\frac{16+2y}{7}$

substituting the following x in 2nd equation (21x + 6y = 24) We get

$21(\frac{16+2y}{7} )+6y=24\\3(16+2y)+6y=24\\48+6y+6y=24\\12y=24-48\\y=-\frac{24}{12} \\y=-2$

Put y= -2 in x equation

$x=\frac{16+2(-2)}{7}\\ x=\frac{16-4}{7}\\\x=\frac{12}{7} \\x=1.71$

Comparing these (x,y) values we can understand that they never meet at a point

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2 years ago

4 pairs of pants for 22.60. what is the unit rate?

Alona [7]

Answer:

$5.65

Step-by-step explanation:

Divide 22.6 / 4.

5.65

Best of Luck!

8 0

2 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

<em>Find the length of DC</em>

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago

I WILL GIFT YOU 30 Brainly (On Jesus)

Tpy6a [65]

Answer:

since highest degree is 2 the degree of a polynomial is also 2.

since the highest exponent is 2 the leading coefficient is 1.

Step-by-step explanation:

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2 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

2 years ago

Read 2 more answers