Given : A baker made 20 pies. A Boy Scout troop buys one–fourth of his pies, a preschool teacher buys one–third of his pies, and a caterer buys one–sixth of his pies.

To find : How many pies does the baker have left?

Solution :

Let x be the number of pies does the baker have left.

According to question,

Number of pies buys,

One-fourth = $\frac{1}{4}$

One-third = $\frac{1}{3}$

One-sixth = $\frac{1}{6}$

i.e. $x=20-(20\times \frac{1}{4}+20\times \frac{1}{3}+20\times \frac{1}{6})$

$x=20-(5+20\times \frac{1}{3}+10\times \frac{1}{3})$

$x=20-(5+\frac{20+10}{3})$

$x=20-(5+ \frac{30}{3})$

$x=20-(5+10)$

$x=20-(15)$

$x=5$

The number of pies does the baker have left is 15.

7 0

2 years ago

How do i get the method on how to solve this x+5(-2)-1

galben [10]

Answer:

I forgot the name but I can show you how to do it lol

Step-by-step explanation:

x+5(-2)-1

x-10-1 we multiplied 5 and -2

x-11

x=11

how I did the last one is there is a non-existent 0 with an equal sign like my teacher says so we added 11 to both sides.

8 0

1 year ago