Write the following equation in slope-intercept form 3x=-2y+4

To celebrate his soccer team's last game of the season, Grayson is making 4 batches of

s2008m [1.1K]

multiply 500 by 4 to know how much is needed in grams first

500×4 = 2000

convert 2000grams to kilograms

since 1000grams make 1 kilograms....then divide 2000 by 1000

which would give you 2000/1000

answer = 2kg of sugar

8 0

3 years ago

Enny’s mother is 5 years older than twice Jenny's age. The sum of their ages is 62 years. This is represented by the equation x

pickupchik [31]

X + 2x + 5 = 62 which can be turned into.
3x + 5 = 62
-5 -5 now we subtract 5 from each side
3x = 57
/3 /3 now we divide 3 from each side to get...
x = 19.
Now to check 19 + (2 x 19) + 5 does in fact equal 62. Jenny is 19 years old. Hope this helped.

3 0

3 years ago

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Which of the following random variables should be considered continuous? Select one: a. The number of cars owned by a randomly c

kolbaska11 [484]

The Random Variable that should be considered continuous is "The time it takes for a randomly chosen athlete to run 200 meters" , the correct option is (c) .

In the question ,

four random variables are given , we have to select the random variable that is continuous .

A Continuous Random Variable is a random variable X , which can take any value in its domain or in an interval or the union of intervals on the real line is called Continuous random variable .

For Example : weight of middle aged people lying between 40 Kg and 150 Kg .

From the given options ,

the option (c) , the time taken for a randomly chosen athlete to run 200 meters is a interval of time ,

So ,it is can be called as Continuous Random Variable .

Therefore , the option that represents Continuous Random Variable is option(c) .

The given question is incomplete , the complete question is

Which of the following random variables should be considered continuous ? Select one:

(a) The number of cars owned by a randomly chosen adult male

(b) The number of orders received by a mail-order company in a randomly chosen week

(c) The time it takes for a randomly chosen athlete to run 200 meters

(d) The numbers of brothers a randomly chosen person has .

Learn more about Continuous Random Variable here

brainly.com/question/17238189

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3 0

1 year ago

Resolver la ecuación trigonometrica: Senx^2=Cosx^2-Senx

Arisa [49]

I would help but I don't speak your language do u speak English not being mean

8 0

4 years ago

The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.

NISA [10]

Answer:

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8.2$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.2$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

8 0

3 years ago

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