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Mekhanik [1.2K]
3 years ago
9

Write the following equation in slope-intercept form 3x=-2y+4

Mathematics
1 answer:
Lorico [155]3 years ago
5 0
The form is y=mx+b

3x=-2y+4 (add 2y)

3x+2y=4 (subtract 3x)

2y=-3x+4 (divide by 2)

y= -2/3x+2
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s2008m [1.1K]

Answer: Graph D will be correct graph for the given function.

Explanation:

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Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.

Moreover, the degree of the function is even thus the end behavior of the function isf(x)\to+\infty, as x\to-\infty and f(x)\to+\infty as x\to+\infty

In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph f(x)\to-\infty, as x\to-\infty and f(x)\to-\infty, as x\to+\infty.) so, it can not be the graph of given function.

In graph B,  neither  it has four root nor it has the end behavior same as function f(x).(because in this graph f(x)\to+\infty as  x\to-\infty and f(x)\to-\infty as x\to+\infty.) so, it can not be the graph of given function.

In graph C, neither  it has four root nor it has the same end behavior as function f(x).(because in this graph f(x)\to-\infty as  x\to-\infty and f(x)\to+\infty asx\to\infty.) so, it also can not be the graph of given function.

In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).

Thus, graph D is the graph of given function.



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Step-by-step explanation:

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