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swat32
3 years ago
7

The sum of the first n Fibonacci numbers with odd indices is

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0
<span>The answer to this question is: f1 + f3 +...+ f2n-1 = f2n</span>

If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)
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What does 1/2(4-14y)=y+50 equal
schepotkina [342]

Step-by-step explanation:

1/2(4-14y)=y+50

1/(8 - 28y) = y + 50

8y - 400 - 28y² +

Now you can solve

3 0
3 years ago
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I need help with this I need to find Area and perimeter
const2013 [10]

Answer:

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(Use Sine and Cosine to find the side lengths.)

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3 0
3 years ago
A recipe requires 1/3 cup of milk for each 1/4 cup of water.How many cups of water are needed for each cup of milk?
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3/4
Work
1/4+1/4+1/4=3/4
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7 0
3 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
Stephanie is training for a race in the summer. Every day she jogs the same number of miles. She also rides her bicycle 6.5 mile
dangina [55]

Answer:

Answer is 910

jkkjkjkkkjkkj

Step-by-step explanation:

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3 years ago
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